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II Review | Constants A solution is 0.070 M in Pb2+. - Part A What minimum concentration of Cl~ is required to begin to preci

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Answer #1

cocnentration of [Pb²⁺] = 0.070 M.
Ksp of PbCl2 = 1.17·10⁻⁵.

PbCl₂(s) → Pb²⁺(aq) + 2Cl⁻(aq)
Ksp = [Pb²⁺] · [Cl⁻]².
[Cl⁻] = √(Ksp ÷ [Pb²⁺]).
[Cl⁻] = √0.0000117 ÷ 0.07.
[Cl⁻] = 1.29·10⁻² M.

Hence option C is correct

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