Potential energy=kq1q2/r
a)There will be 3 energy terms
=kq(-4q/r)+kq(-4q/r)+k(-4q)(-4q/2r)
=zero
Clearly the summation=zero
b)Since net force on each particle is zero, no energy is required to move any particle so potential energy of system=zero
c)New potential energy
=kq(-5q/r)+kq(-5q/r)+k(-5q)(-5q/2r)
=2.5kq/r
given r=L
So new potential energy=2.5kq/L
Part a b and c please explain ASAP -4q +q -4q (b) Explain your answer to...
please explain the steps as well! it’s imp for me to understand
this question. i have attached the table for last part of the
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