The concept used to solve this problem is perfectly elastic head-on collision.
In the case of perfectly elastic collision, both momentum and kinetic energy are conserved quantities. Because of the collision, there is no net loss in kinetic energy in the system
Use conservation of momentum and conservation of kinetic energy to deduce the equations for before and after collision.
Finally use these equations to find speed of the first marble and second marble immediately after the collision.
A marble moving with an initial speed strikes another marble at rest. Assuming the collision is perfectly elastic and the marble collide head-on.
From the conservation of momentum,

Here,
is the mass of the first marble,
is the mass of second marble,
is the initial speed of the first marble,
is the initial speed of the second marble,
is the final speed of the first marble, and
is the final speed of the second marble.
Substitute
for
in the conservation of momentum equation, because second marble initial at rest.

…… (1)
From conservation of energy,

Substitute
for
.

Substitute algebraic identity
for
.
…… (2)
Divide the equation (2) by (1).

…… (3)
Substitute equation (3) in (1).

Rearrange the above equation to get final speed of the first marble,

Substitute equation
for
in equation (1).

Rearrange the above equation to get final speed of the second marble,

(A)
Expression for the final speed of the first marble immediately after collision is,

Substitute
for
,
for
, and
for
.

Therefore, the final speed of the first marble immediately after collision is
.
(B)
Expression for the final speed of the second marble immediately after collision is,

Substitute
for
,
for
, and
for
.

The final speed of the first marble immediately after collision is
.
The final speed of the second marble immediately after collision is
.
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