Question

Part A

What is the strength of the electric field at the position indicated by the dot in (Figure 1) ?

Answer 1

at the given point each charge produces equal magnitude of elctric field.

E = k*q/d^2

= 9*10^9*1*10^-9/(2*0.05^2)

= 1800 N/c

angle between the two elctric field vectors is 90 degrees.

so, net magnetic field, Enet = sqrt(E^2 + E^2)

= sqrt(2)*E

= 1.414*1800

= 2545.6 N/c

direction : towards +x axis