Question

400a A12% 12.70-mars/400 I00/. 0-12-mas 400 0.12 x 400 4 a) 4.80 g b) 48.0 g c) 352 g 12) What is the molality of a solution prepared by dissolving 40.0 g of glucose (C6H12O6) in 4.00 kg of water? (2 points, show calculation) a) 0.0555 m b) 10.0 m c) 0.0100 m d)0.222 m 4-0/452.091/4 13) One liter of 2.0 M KCl solution and two liters of 1.0 M KCI solution have the same a) density. b) concentration.

Answer 1

molalith = mol solute man soldent (kg) mol glucost = you = 0.22 mol molality = 0.22 0.22 4.0 - v. 0555 m 0.0555 m