The force on a particle is directed along an x axis and given by F =...

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The force on a particle is directed along an x axis and given by F =...

The force on a particle is directed along an x axis and given by F = F₀(x/x₀ - 1) where x is in meters and F is in Newtons. If F₀ = 1.6 N and x₀ = 2.0 m, find the work done by the force in moving the particle from x = 0 to x = 2x₀ m.

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Answer 1

Answer #1

F = Fo(X/Xo - 1)

F = 1.6*(x/2 -1)

Work done W = (integral from x = 0 to x = 2xo)(F*dx)

W = (integral from x = 0 to x = 2xo)(1.6*(x/2 -1)*dx)

W =(from x = 0 to x = 2xo)1.6*(x^2/4 - x)(from x = 0 to x = 2xo)

W = 1.6*(4*xo^2/4 - 2xo)-(0-0)

W = 1.6*(xo^2 - 2xo)

W = 1.6*(2^2-2*2) = 0 J

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Answer 2

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