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1. A perennial stream is a stream that has water flowing in it all the time. The data set presented in Table 1 represents a sample of stream flows in a perennial stream for a 45-day period. These stream flows were measured using a flow meter that has a precision of + 0.1 Cfs. Find the following statistical parameters for the sample data given in Table 1 a. Central Tendency i. Mean the average value of the random variable. ii. Median the value of the random variable that is in the middle of the sample set. Mode the value of the random variable that occurs most ili. b. Dispersion an average measure of the deviation about the mean i. li. c. Asymmetry Variance squared. Standard deviation the mean. an average measure of the deviation about i. Skew a measure of the symmetry or asymmetry of the sample data about the mean 2. Graphical Representation of Data: Given the data presented in Table 1, develop the following a. Histogram- use an interval of 2 Cfs b. Box Plot-are there any outliers? Table 1 Flow (Cfs) 31 31-Mar-18 8.3 32 1-Apr-18 1343.1 33 2-Apr-181098. PointDate Point Date Point Date 1 1-Mar-18 16 16-Mar-18 | 1249.6 17 17-Mar-18 922.1 181 18-Mar-181 77 19 19-Mar-18 1332.1 20 20-Mar-18 501.1 21 21-Mar-18 1497.9 22 22-Mar-18 1373.9 23 23-Mar-18 1187.4 24 24-Mar-18 746.3 25 25-Mar-18 1345.4 26 26Mar-18 1297.7 27 27-Mar-18 851.5 28 28-Mar-18 1185.2 29 | 29-Mar-18 606.6 30 30-Mar-18512.9 856.5 2-Mar-18 1169.8 3-Mar-18 826.0 547.2 4-Mar-18 922 5-Mar-18 6-Mar-18 34 3-Apr-18 1347.0 35 4-Apr-18 14736 36 SApr-18516.0 37 6-Apr-18 1096.0 1318.0 519.5 38 -Apr-18 5016 8 8-Mar-18 9-Mar-18 1119.7 10 10-Mar-18 791.1 11 11-Mar-18 1492.4 12 12-Mar-18 1028.3 13 13-Mar-18 965.7 14 14-Mar-18 1112.3 15 15-Mar-18 814.7 39 8-Apr-18 797.4 40 9-Apr-18 743.3 41 10-Apr-18719.3 42 11-Apr-18 650.8 43 12Apr-18 1154.8 695.8 1277.2 45 I 14-Apr-18
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(i) mean: χ·ござ th 2 maximum Valu oc A. G viun n-) に) 3) Standard dtuì ation σ:hE(24-X ) 2. , n-1 に) euun (n-)in-2)

Variable   Mean       StDev     Variance    Median    Mode     Skewness

               944.4         323.4     104593.3      905.7     1492.4     -0.14

uysrJSFAEAnrfLy0stQABAegQgACA5AhAAkBwBCA

cQBJpvqQAAAABJRU5ErkJggg==

Outliers are not present in data

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