Question

5. Consider the following compounds: a) CH(CH).CH c) CHEECH b) CH.CHEH d) Chu(CH.EOH 1) CH.(CH2)CN .) CH (CH2).CH-CHCH, 9) C&H OH hộ CH (CH2)-N(CHnha 1) CH.CH CH,CH.CHEN(CH2CH2CH3)2 k) CH3CH2OH » CH(CH2)EOCH Which one(s) of the above would be soluble in water? Which one(s) would not be soluble in water but would be soluble in 5% HCI? Which one(s) would not be soluble in water but would be soluble in 5% NaOH? Which one(s) would not be soluble in water but would be soluble in 5% NaHCO,? Which one(s), which are not soluble in anything else, would be soluble in concentrated H2SO4?

Answer 1

0 Molecules which can make strong bond with water molecule will be soluble in water. Among given molecules CH₃CH2OH can make strate bond with water molecule. Hence CH₃CH2014 (6) will be water soluble. CH3cOct, (c) also water soluble for same reason. @ 5%. Hel solution is a acidic solution. So it can protonate the 'N' of an amine and will make a chloride salt of the amine, which eventually will be water soluble. Ayo CH3 (CH2), N(CH2CH2CH3)2 + Hel CH3 (CH2), & (CH2 CH2 CH3)2 Amine (h) - chloride salt of the arrine SOBCHz EHU), N CH C CH3)2 will be soluble in 5%. Hal. 57. Nodt solution will be reacting with phenol (Coltsolt (g) and will form sodium phenoxide ishich is water soluble. OH - 21 + NAOH - + H2O Phenol sodium pheroxide (wator soluble. so C6H5OH (1) will be soluble in sy nooit solution. NahCoa will react with acid and form sodium salt of the acid and make the acid soluble in NattlO3 solution, - CH3CH2), 200H & Nalt (O3 CH(CH2), LOONa+ CO₂ + H2O So city (Ct), COOH (d) will be soluble in Nalt (O3 solution. strong acid H2SO, can profonate amide and make a salt which will be soluble in conc. H2SO4. I Chces.com&nuck4), 1604, [Cnca con le casuahil sa So I will be soluble in cone. H2SO4.