Homework Answers
A)
Average speed, v = 710/197 = 3.60 m/s
B)
Displacement, d = - 710 m
C)
Average velocity, V = - 710/197 = - 3.60 m/s
D)
Average acceleration, a = - 30 - 0/197 = - 0.15 m/s^2
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19 11:00:00 AM moving in the same direction and by time tr 197 s has covered...
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