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Explain how dissolving the Group IV carbonate precipitate with 6M CH3COOH, followed by the addition of...

Explain how dissolving the Group IV carbonate precipitate with 6M CH3COOH, followed by the addition of extra acetic acid, establishes a buffer with a pH of approximately 5.
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Answer #1

Dissolving the Group IV carbonate in acetic acid gives acetate ions:

MCO3(s) + 2 CH3COOH(aq) => M2+(aq) + 2 CH3COO-(aq) + H2O(l) + CO2(g)

Adding excess acetic acid gives a final solution containing both:

CH3COOH and its conjugate base CH3COO-

Such a solution is a buffer solution.

Henderson-Hasselbalch equation:

pH = pKa + log([CH3COO-]/[CH3COOH])

pKa of CH3COOH = 4.75

If [CH3COO-]/[CH3COOH] = 1,

then pH of buffer = 4.75 + log(1) = 4.75 ≈ 5

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