Question

Answer = 12nC

In the figure, all the charges are point charges and the charge in the middle is Q = -3.1 nC. For what charge q1 will charge q2 92 be in static equilibrium?

Answer 1

ANSWER

Exercise Information:

$Q=-3.1nC$

$r=0.1m$

$q_{1}=?$

For charge q₂ to be in static equilibrium the force exerted by the charge Q has to be equal to that of q₁. And opposite of direction:

$F_{Q-q_{2}}=F_{q_{1}-q_{2}}$

$\frac{k(3.1x10^{-9})q_{2}}{(0.1^{2})}=\frac{kq_{1}q_{2}}{(0.2^{2})}$

$q_{1}=\frac{3.1x10^{-9}(0.2^{2})}{(0.1^{2})}$

$\mathbf{q_{1}=12.4nC\approx 12nC}$

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