Question

Suppose a 0.390 kg ball is thrown at 17.0 m/s to a motionless person standing on ice who catches it with an outstretched arm as shown in the figure below. (a) Calculate the final linear velocity (in m/s) of the person, given his mass is 90.0 kg x m/s 07 (b) What is his angular velocity (in rad/s) if each arm is 3.00 kg? You may treat the ball as a point mass and treat the person's arms as uniform rods (each has a length of 0.810 m) and the rest of his body as a uniform cylinder of radius 0.140 m. Neglect the effect of the ball on his center of mass so that his center of mass remains in his geometrical center x rad/s 244 (c) Compare the initial and final total kinetic energies. O Initial kinetic energy is greater than final kinetic energy. O Initial kinetic energy is the same as final kinetic energy. Initial kinetic energy is less than final kinetic energy.

Answer 1

0.390 x 17 mu 0.0733 m/s (a)0mu = (m+m) (m+m') 90+0.390 0.390 x 17 x 0.810 mur 3.813 rad/s (b)w [0.33 x 3 x 0.8103] +[0.5 x 90 x 0.1402 Iarm+Ibody (c)KEinitial KE final I hope you will find the answer useful. Please rate. cheers.