Question

Assume the magnitude of the electric field on each face of the cube of edge L- 1.07 m in the figure below is uniform and the directions of the fields on each face are as indicated. (Take El-31.8N/c and E,-23.5 NC.) E2 20.0 N/C 20.0 N/C Ei 20.0 N/C 50N/C (a) Find the net electric flux through the cube. N m2/c (b) Find the net charge inside the cube. (c) Could the net charge be a single point charge? O Yes O No
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Answer #1

answer) a) we know the formula

\phi=EA

so at the top

\phi1=-23.5N/C*1.072=-26.90515 N.m2/C

at the left side of the cube

\phi2=20N/C*1.072=22.898N.m2/C

at the back side

\phi3=20N/C*1.072=22.898Nm2/C

at the right side

\phi4=-31.8N/C*1.072= -36.40782N.m2/C

at the bottom side

\phi5=15N/C*1.072=17.1735N.m2/C

at the front side

\phi6=20N/C*1.072=22.898Nm2/C

so the net flux through the cube=\phi1+\phi2+\phi3+\phi4+\phi5+\phi6=22.55 N.m2/C

so the answer is 22.6Nm2/C or 23 N.m2/C or 22.55Nm2/C

b) we have the formula

\phie=qin/\epsilon0

so qin=\phie*\varepsilono=22.55*8.85*10-12C2/Nm2=1.996*10-10C

so the answer is 1.996*10-10C or 2.00*10-10C or 2.04*10-10C

c) the correct option is=yes.

its because the flux through  the cube is not symmetrical.

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