Question

Writing equations of lines parallel and perpendicular to a given... Consider the line y=-6x+5. Find the equation of the line that is parallel to this line and passes through the point (8, -4). Find the equation of the line that is perpendicular to this line and passes through the point (8, -4). Note that the ALEKS graphing calculator may be helpful in checking your answer. Equation of parallel line: e X Equation of perpendicular line: 1 ? Explanation Check 20:20 Mc Education All Rio > The They $ & N 3 & 4 5 6 7 8 9 W

Answer 1

y = -6x + 5 1) the The equation of a line that is parallel to line (1) is Y = -6x + c [as, as, slope of the both (2) lines are equal]. The line (2) passes through the point (8,-4) 50, - 4 = -6x 8 te • 4 +48 7 44 The equation of line which is parallel to line - 6x + and passes through the point is y - 6x + 44 4 2) line :) to (1) ] tere mi The -4. te 3 The equation of a which is perpendicular y=&x+ch as the product of slope of two perpendicular line is -1, mim2=-1 let -6 then -6Xm2 = m2 = 16 line (3) passes through the point (8,-4) then + x 8 e. -4- = -(4+4)--" The equation of a line that is par perpendic Cular to 1 and passes through the the point (8,-4) is yox 16 =x-32 7x-by=32 o Equation of paralled line : y = -6x + 44 6x + y -44 Equation of perpendicular line: y=6x - 16 x-by = 32 64 3 oro, Or,