Consider the circuit modeled by the differential equationwith initial conditions Q(0) = Q0...

Consider the circuit modeled by the differential equation

with initial conditions Q(0) = Q0 and I(0) = 0. Note that the substitution I' = Q" is not much use, because we have not yet learned how to solve second-order differential equations. However, you can use the chain rule to show that I′ = I(dI/dQ), and this substitution will make equation (4.9) separable. Solve the resulting equation for 7 in terms of Q; then solve this result for Q in terms of t. Finally, find the current as a function of t.