Two tanks, Tank I and Tank II, are filled with V gal of pure water. A solution containing a lb of salt per gallon of water is poured into Tank I at a rate of b gal per minute. The solution leaves Tank I at a rate of b gal/min and enters Tank II at the same rate (b gal/min). A drain is adjusted on Tank II and solution leaves Tank II at a rate of b gal/min. This keeps the volume of solution constant in both tanks (V gal). Show that the amount of salt solution in Tank II, as a function of time t, is given by aV – abte–(b/V)t – aVe–(b/V)t.
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