Solve the problem. See Example.
EXAMPLE Dividing a Board into Pieces
A project calls for three pieces of wood. The longest piece must be twice the length of the middle-sized piece. The shortest piece must be 10 in. shorter than the middlesized piece. If a board 70 in. long is to be used, how long can each piece be?
Step 1 Read the problem. There will be three answers.
Step 2 Assign a variable. Since the middle-sized piece appears in both pairs of comparisons, let x represent the length, in inches, of the middle-sized piece.
A sketch is helpful here. See FIGURE 2.
FIGURE 2
Step 3 Write an equation.
Step 4 Solve.
Step 5 State the answer. The middle-sized piece is 20 in. long, the longest piece is 2(20) = 40 in. long, and the shortest piece is 20 − 10 = 10 in. long.
Step 6 Check. The lengths sum to 70 in. All problem conditions are satisfied.
In triangle ABC, the measure of angle A is 141° more than the measure of angle B. The measure of angle B is the same as the measure of angle C. Find the measure of each angle. (Hint: See Exercise.)

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