Problem

(Continuation) From the following table of values of ln x, interpolate to obtain ln 2.35...

(Continuation) From the following table of values of ln x, interpolate to obtain ln 2.352 and ln 2.387 using the Newton forward difference form of the interpolating polynomial:

Using the correctly rounded values ln 2.352 ≈ 0.85527 and ln 2.387 ≈ 0.87004, show that the forward-difference formula is more accurate near the top of the table than it is near the bottom.

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Solutions For Problems in Chapter 4.1

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