Problem

(Continuation) The computation of ex can be reduced to computing eu for |u| < (ln 2)/...

(Continuation) The computation of e^x can be reduced to computing e^u for |u| < (ln 2)/2 only. This algorithm removes powers of 2 and computes e^u in a range where the series converges very rapidly. It is given by

e ^x = 2^me^u

where m and u are computed by the steps

Here the minus sign is used if x < 0 because z < 0. Incorporate this range reduction technique into the code.

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Solutions For Problems in Chapter 2.2

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