Given the following definitions,
char cval; int ival; unsigned int ui;float fval; double dval;
identify the implicit type conversions, if any, taking place:
(a) cval = ‘a’ + 3;
(b) fval = ui - ival * 1.0;
(c) dval = ui * fval;
(d) cval = ival + fval + dval;
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