In a department store toy display, a small disk (disk 1) of radius 0.100 m is driven by a motor and turns a larger disk (disk 2) of radius 0.500 m. Disk 2, in turn, drives disk 3, whose radius is 1.00 m. The three disks are in contact, and there is no slipping. Disk 3 is observed to sweep through one complete revolution every 30.0 s.

a) What is the angular speed of disk 3?
b) What is the ratio of the tangential velocities of the rims of the three disks?
c) What is the angular speed of disks 1 and 2?
d) If the motor malfunctions, resulting in an angular acceleration of 0.100 rad/s2 for disk 1, what are disks 2 and 3 s angular accelerations?
THINK:
The angular speed of the disk
can be calculated by considering the time period of the disk
. All the three disks are in contact, and there is no slipping. Hence, all the three disks are having same tangential speeds. By using the radius of the disks and the tangential speeds, we can calculate the angular speeds of the disks
and
. The angular acceleration of the disks can be calculated by using the tangential acceleration of the disk.
SKETCH:
The sketch for given problem is shown in the below figure.
RESEARCH:
is given by the equation
…… (1)Here
is the time period of the disk 3.
(b) All the three disks have the same tangential speeds. Hence it is given by the equation
…… (2)
Here
and
are the radius and angular speed of the disk 3.
(c)The angular speeds of the disks
and
are given by the equations
…… (3)
Here
and
are the radius of the disk 1 and disk 2 respectively and
is the tangential acceleration of the each of the disks
(d)The tangential acceleration of all disks is equal. Therefore, the tangential acceleration of the disk
is given by the equation

Hence, the angular acceleration of the disk’s
and
is given by the equation
…… (4)
Given data:
The radius of the disk
,
The radius of the disk
,
The radius of the disk
,
The time period of the disk
,
The angular acceleration of the disk
,
CALCULATE
(a)
Now, substituting the numerical values in the equation (1), we get the angular speed of the disk

(b)
Now, substituting the numerical values in the equation (2), we get the tangential speeds of the disks
(c)
Now, substituting the numerical values in the equation (3), we get angular speeds of the disks


(d)
The tangential acceleration of the disk’
’is given by the equation

Now, substituting the numerical values in the equation (4), we get angular accelerations of the disks
and
.

