Question

Consider a multiple-choice examination with 50 questions. Each question has four possible answers. Assume that a student who has done the homework and attended lectures has a 75% probability of answering any question correctly.

1. A student must answer 43 or more questions correctly to obtain a grade What percentage of the students who have done their homework and attended lectures will obtain a grade A on this multiple-choice examination?
2. A student who answers 35 to 39 questions correctly will receive a grade of C. What percentage of students who have done their homework and attended lectures will obtain a grade of C on this multiple-choice examination?
3. A student must answer 30 or more questions correctly to pass the examination. What percentage of the students who have done their homework and attended lectures will pass examination?
4. Assume that a student has not attended class and has not done the homework for the course. Furthermore, assume that the student will simply guess at the answer to each question. What is the probability that this student will answer 30 or more questions correctly and pass the examination?

Answer 1

Date Given that n = 50 p = 0.75 ne = sox 0.75 = 37.5 ng = sox0.25 = 12.5 75 S - He can use Binomial apRTOX1 Binomial approximation to normal. mean = = nx P = 37.5 standard deviation = 3 = rnpa = 3-0 61g. Pix 243) using continuity corrective foretr. PCX742.5) =plx-ul 6 42.5-37-5 ) 3.oglg = 8(271.6330) = 1- Plz<1.6330) - = I- o.9488 0.0512 1.6330 ... In percentage = 15.12 %)

Page No. Date е[ 25 схез) HPL 33.5 х 33 ] ( 1 < 3 3s. S - 31.5 3. осія .5 - 7: 5 2.6 6 1 9 - 0.65 32 4 z o. 32 Gs эр) 24 0.3266) — [22-о- - о. 62.30 - 0.25 63 = 0.37) дресе мае = 37.12 1 - 0-6532 - 0-6532 а: 326 ҳ22 = P [x224-s) - - 2 5 5 - 375 3:06 - - АН- -26 1 2 3 4 - е[ 2) - 2 - G13 2 1 - РСz - 2.6 tag T - 1 - o.oods - о. 99ЅЅ. — In perce Age : 99. гл.

Date student does not do homework. = I-p*23.) = 1-0.9955 =10.0045