Mechanic sells a brand of automobile tire that has a lifeexpectancy that is normally distributed,...
Mechanic sells a brand of automobile tire that has a life expectancy that is normally distributed, with a mean life of 27,000 miles and a standard deviation of 2200 miles. He wants to get into a free replacement of tires That don’t wear well. How Should he word his guarantee if he is willing to replace approximately 10% of the tires?
Tires that wear out by miles will be replaced free of charge. (Round to the nearest mile as needed.)
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Mechanic sells a brand of automobile tire that has a lifeexpectancy that is normally distributed,...
A mechanic sells a brand of automobile tire that has a life expectancy that is normally...
A mechanic sells a brand of automobile tire that has a life expectancy that is normally distributed, with a mean life of 29 comma 000 miles and a standard deviation of 2800 miles. He wants to give a guarantee for free replacement of tires that don't wear well. How should he word his guarantee if he is willing to replace approximately 10% of the tires? Tires that wear out by [ ] miles will be replaced free of charge. (Round...
A mechanic sells a brand of automobile tire that has a life expectancy that is normally...
A mechanic sells a brand of automobile tire that has a life expectancy that is normally distributed, with a mean life of 30,000 miles and a standard deviation of 2800 miles. He wants to give a guarantee for free replacement of tires that don't wear well. How should he word his guarantee if he is willing to replace approximately 10% of the tires?
O A mechanic sells a brand of automobile tire that has a life expectancy that is...
O A mechanic sells a brand of automobile tire that has a life expectancy that is normally distributed, with a mean life of 31,000 miles and a standard deviation of 2700 miles. He wants to give a guarantee for free replacement of tires that don't wear well. How should he word his guarantee if he is willing to replace approximately 10% of the tires? Click to view page 1 of the table. Click to view page 2 of the table....
23. A mechanic sells a brand of automobile tire that has a life expectancy that is...
23. A mechanic sells a brand of automobile tire that has a life expectancy that is normally distributed, with a mean life of 35,000 miles and a standard deviation of 2800 miles. He wants to give a guarantee for free replacement of tires that don't wear well. How should he word his guarantee if he is willing to replace approximately 10% of the tires?
26 of 26 (10 complete) This Test: 26 pts possi This Question: 1 pt distributed, with...
26 of 26 (10 complete) This Test: 26 pts possi This Question: 1 pt distributed, with a mean life of 29.000 miles and a standard deviation of 2500 miles, He wants to aive a quarantee for free replacement of tires that don't wear automobile tir well. How should he word his guarantee if he is willing to replace approximately 10 % of the tires? Click to view page 1 of the table. Click to view page 2 of the table....
The lifetime of a certain type of automobile tire (in thousands of miles) is normally distributed...
The lifetime of a certain type of automobile tire (in thousands of miles) is normally distributed with a mean of 32 and a standard deviation of 4. Round to the second. a) Find the 50 percentile of tire lifetimes. b) Find the tire life that has 70% above it. c) Find the two tire lives that hold the middle 15% Lower Upper d) The tire company wants to guarantee that its tires will last a certain number of miles. What...
The lifetime of a certain type of automobile tire (in thousands of miles) is normally distributed...
The lifetime of a certain type of automobile tire (in thousands of miles) is normally distributed with mean = 41 and standard deviation = 4. Use the TI-84 Plus calculator to answer the following. (a) Find the 21st percentile of the tire lifetimes. (b) Find the 73rd percentile of the tire lifetimes. (c) Find the first quartile of the tire lifetimes. (d) The tire company wants to guarantee that its tires will last at least a certain number of miles....
STATISTICS QUIZ 6 NAME 1. The average life of a brand of automobile tire is 30,000...
STATISTICS QUIZ 6 NAME 1. The average life of a brand of automobile tire is 30,000 miles, with a standard deviation of 2,800 miles. Ir a tire is randomly selected and tested, find the probability that it will last for more than 34,000 miles. Assume the lifetime of tires is normally distributed 2. If the tires in problem #1 are to be guaranteed, so that only 4% will have to be replaced for having to short a lifetime, how long...
A tire company finds the lifespan for one brand of its tires is normally distributed with...
A tire company finds the lifespan for one brand of its tires is normally distributed with a mean of 48,400 miles and a standard deviation of 5,000 miles. Find the probability of a tire lasting more than 57,000 miles.
the lifetime of a certain type of automobile tire (in thousands of miles)is normally distributed with...
the lifetime of a certain type of automobile tire (in thousands of miles)is normally distributed with a mean of 39 and a standard deviation of 4. a. find the 24th percentile of tire lifetimes b. find the 76th percentile of tire lifetimes c.find the 3rd quartile of the tire lifetimes d.what number of miles in thousands should the company guarantee so that only 3% of the tire violatethe guarantee round answers to two decimal places
O A mechanic sells a brand of automobile tire that has a life expectancy that is normally distributed, with a mean life of 31,000 miles and a standard deviation of 2700 miles. He wants to give a guarantee for free replacement of tires that don't wear well. How should he word his guarantee if he is willing to replace approximately 10% of the tires? Click to view page 1 of the table. Click to view page 2 of the table....
26 of 26 (10 complete) This Test: 26 pts possi This Question: 1 pt distributed, with a mean life of 29.000 miles and a standard deviation of 2500 miles, He wants to aive a quarantee for free replacement of tires that don't wear automobile tir well. How should he word his guarantee if he is willing to replace approximately 10 % of the tires? Click to view page 1 of the table. Click to view page 2 of the table....
The lifetime of a certain type of automobile tire (in thousands of miles) is normally distributed with a mean of 32 and a standard deviation of 4. Round to the second. a) Find the 50 percentile of tire lifetimes. b) Find the tire life that has 70% above it. c) Find the two tire lives that hold the middle 15% Lower Upper d) The tire company wants to guarantee that its tires will last a certain number of miles. What...
STATISTICS QUIZ 6 NAME 1. The average life of a brand of automobile tire is 30,000 miles, with a standard deviation of 2,800 miles. Ir a tire is randomly selected and tested, find the probability that it will last for more than 34,000 miles. Assume the lifetime of tires is normally distributed 2. If the tires in problem #1 are to be guaranteed, so that only 4% will have to be replaced for having to short a lifetime, how long...
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