1.) Find the area under the standard normal curve between -1.37 and the mean, P(-1.37 < z < 0.00). (Give your answer correct to four decimal places.)
2.) Find the area under the standard normal curve between z = -1.89 and z = 1.21, P(-1.89 < z < 1.21). (Give your answer correct to four decimal places.)
3.) Find the area under the standard normal curve between z = -2.57 and z = 1.51, P(-2.57 < z < 1.51). (Give your answer correct to four decimal places.)
I have used the Z tables to solve the problem. Here' one for you reference:
http://sixsigmastudyguide.com/wp-content/uploads/2014/04/z-table.jpg
All calculations in detail are below:
1. P(-1.37<Z<0) = P(Z<=0) - P(Z<=-1.37) = .50 - 0.0853 = 0.4147
2. P(-1.89<Z<1.21) = P(Z<=1.21) - P(Z<=-1.89) = 0.8869 - 0.0294 = 0.8575
3. P(-2.57<Z<1.51) = P(Z<=1.51) - P(Z<=-2.57) = 0.9345 - 0.0051 = 0.9294
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