Question

calculate phenotype frequencies, allele frequencies, genotype frequencies in 5th generation

Environment: Clean Forest

	Moths Released	G1	G2	G3	G4	G5
Typica	250	166	259	372	521	851
Carbonaria	750	308	254	234	210	199
Total	1000	474	513	606	731	1050

Phenotype Frequency

	Color	Initial Frequency	Frequency G5 (Round to 2 decimal places)
Typica	White	0.25
Carbonaria	Black	0.75

Allele Frequency

	Allele Frequency	Initial allele frequency	G5 Allele Frequency (Round to 2 decimal places)
q	d	0.50
p	D	0.50

Genotype Frequency

	Moths	Genotypes	Color	Moths released	Initial Frequency	Frequency G5	Number of moths G5
q2	Typica	dd	White	250	0.25
2pq	Carbonaria	Dd	Black	500	0.50
q2	Carbonaria	DD	Black	250	0.25

Answer 1

Phenotype Frequency

	Color	Initial Frequency	Frequency G5 (Round to 2 decimal places
Typica	White	0.25	851/1050= 0.81
Carbonaria	Black	0.75	199/1050= 0.19

Allele Frequency

	Allele Frequency	Initial allele frequency	G5 Allele Frequency (Round to 2 decimal places)
q	d	0.50	Square root of 0.81= 0.9
p	D	0.50	1-0.9= 0.1

Genotype Frequency

	Moths	Genotypes	Color	Moths released	Initial Frequency	Frequency G5	Number of moths G5
q​​​​​​2	Typica	dd	White	250	0.25	(0.9*0.9)= 0.81	0.81*1050= 850.5
2pq	Carbonaria	Dd	Black	500	0.50	2*0.81*0.19= 0.31	0.31*1050= 325.5
q​​​​​​2	Carbonaria	DD	Black	250	0.25	0.1*0.1= 0.01	0.01*1050= 10.5 ​​​​​​

Answer 2

Calculate phenotype frequencies in 5th generation. Record in Lab Data