Question

Consider the following reaction:

CO(g)+2H2(g)⇌CH3OH(g)

The reaction between CO and H2 is carried out at a specific temperature with initial concentrations of CO = 0.26 M and H2 = 0.52 M. At equilibrium, the concentration of CH3OH is 0.11 M.

Find the equilibrium constant at this temperature

Answer 1

For a Reaction aA + bB cC + dD equilibrium Constant k ed' [0] 10.CD], 1), (B) are the A B) I Concentrations of the componants] Ta, b, c, d are the number of moles of the corresponding Componants Here, C0 () + 2 H29 CH, OH (3) so all are in same, phase (gas). equilibrium constant k [eH;oH] [Hz] ² [co] Moleculer weight- co + 2H2 - CH₂OH For 1 mol 28.01g 1 mol Hence, 101N 022! o. lIM ->At equilibrium 48 2 and 32049 1 and

Hence, 0.1lm of Co(a) reacts with 0.22M of H (9) produce O'LIM CH2OH (7). equilibrium Con of CH OH So, the equilibrium Constant = equilibrium Cone of co x . (equilibrius (conc of н.) Tow, equilibrium Cone - Ş Initical Con – Reacted Con} For H₂ = (0.52-0.22) M - 0.30M For CO = (0.26 -0.11) = 0.15 M 0.15 x 6.30)2 = 0.0135 -8.14 0.ll - 0.11 Hence, K =