Question

How many moles of Na₂SO₄ are in a 0.140 m aqueous solution that was prepared with 2.30 kg of water?

Answer 1

The solution is 0.140 m. Hence, 1 kg (1000 g ) of water (solvent) contains 0.140 moles of sodium sulphate (solute). The conversion factor is .

Aqueous solution was prepared with 2.30 kg of water.

$\text { 2.30 kg water } \times \frac{ \text { 0.140 mol }Na_2SO_4 }{ \text { 1 kg water }}= \text { 0.322 mol }Na_2SO_4$

Hence, 0.322 moles of sodium sulphate are present in a 0.140 m aqueous solution that was prepared with 2.30 kg of water.