balanced chemical equation: 2C8H18(g)+25O2->16CO2(g)+18H2O(g) 0.320 mol of octane is allowed to react with 0.880 mol of...

Question

Question

balanced chemical equation:

2C8H18(g)+25O2->16CO2(g)+18H2O(g)

0.320 mol of octane is allowed to react with 0.880 mol of oxygen. After the reaction how much Octane is left?

science chemistry

Answer 1

Answer #1

$2 CgH189) t 250_ {3 16cor(a) t (s) Accordin to the stoichiomtry ds the esctm moe Or to Produ co 16 octane eects wi th 25moles$

Answer 2

Similar Homework Help Questions

Balanced chemical equation: 2C8H18(g)+25O2(g)->16CO2(g)+18H2O(g) 0.320 mol of octane is allowed to react with 0.880 mol of...

Balanced chemical equation: 2C8H18(g)+25O2(g)->16CO2(g)+18H2O(g) 0.320 mol of octane is allowed to react with 0.880 mol of oxygen. How many moles of water are produced in this reaction?
2C8H18(g)+25O2(g)→16CO2(g)+18H2O(g) 0.260 mol of octane is allowed to react with 0.760 mol of oxygen. Which is...

2C8H18(g)+25O2(g)→16CO2(g)+18H2O(g) 0.260 mol of octane is allowed to react with 0.760 mol of oxygen. Which is the limiting reactant? (i got the limiting reactant of oxygen, but i dont know how to do this next part VVV) part D: After the reaction, how much octane is left?
background info: So I have the balanced equation = 2C8H18(g)+25O2(g)→16CO2(g)+18H2O(g) and oxygen is the limiting reactant...

background info: So I have the balanced equation = 2C8H18(g)+25O2(g)→16CO2(g)+18H2O(g) and oxygen is the limiting reactant of 0.180 mol of octane is allowed to react with 0.880 mol of oxygen. Part C How many moles of water are produced in this reaction? Express your answer with the appropriate units. View Available Hint(s) : HÅR O 2 ? H2O produced = H,0 produced = Value Units Submit Part D After the reaction, how much octane is left? Express your answer with...

The combustion of octane, C8H18,C8H18, proceeds according to the reaction shown. 2C8H18(l)+25O2(g)⟶16CO2(g)+18H2O(l)2C8H18(l)+25O2(g)⟶16CO2(g)+18H2O(l) If 522 mol522 mol...

The combustion of octane, C8H18,C8H18, proceeds according to the reaction shown. 2C8H18(l)+25O2(g)⟶16CO2(g)+18H2O(l)2C8H18(l)+25O2(g)⟶16CO2(g)+18H2O(l) If 522 mol522 mol of octane combusts, what volume of carbon dioxide is produced at 38.0 ∘C38.0 ∘C and 0.995 atm?
The combustion of octane, C8H18,C8H18, proceeds according to the reaction shown. 2C8H18(l)+25O2(g)⟶16CO2(g)+18H2O(l)2C8H18(l)+25O2(g)⟶16CO2(g)+18H2O(l) If 418 mol418 mol...

The combustion of octane, C8H18,C8H18, proceeds according to the reaction shown. 2C8H18(l)+25O2(g)⟶16CO2(g)+18H2O(l)2C8H18(l)+25O2(g)⟶16CO2(g)+18H2O(l) If 418 mol418 mol of octane combusts, what volume of carbon dioxide is produced at 14.0 ∘C14.0 ∘C and 0.995 atm?
The combustion of octane, C8H18,C8H18, proceeds according to the reaction shown. 2C8H18(l)+25O2(g)⟶16CO2(g)+18H2O(l)2C8H18(l)+25O2(g)⟶16CO2(g)+18H2O(l) If 4.10×102 mol4.10×102 mol...

The combustion of octane, C8H18,C8H18, proceeds according to the reaction shown. 2C8H18(l)+25O2(g)⟶16CO2(g)+18H2O(l)2C8H18(l)+25O2(g)⟶16CO2(g)+18H2O(l) If 4.10×102 mol4.10×102 mol of octane combusts, what volume of carbon dioxide is produced at 12.0 ∘C12.0 ∘C and 0.995 atm?

The combustion of octane, C8H18, proceeds according to the reaction shown. 2C8H18(l)+25O2(g)⟶16CO2(g)+18H2O(l) If 442 mol of...

The combustion of octane, C8H18, proceeds according to the reaction shown. 2C8H18(l)+25O2(g)⟶16CO2(g)+18H2O(l) If 442 mol of octane combusts, what volume of carbon dioxide is produced at 19.0 ∘C and 0.995 atm? ?=
The combustion of octane, C8H18, proceeds according to the reaction shown. 2C8H18(l)+25O2(g)⟶16CO2(g)+18H2O(l) If 498 mol of...

The combustion of octane, C8H18, proceeds according to the reaction shown. 2C8H18(l)+25O2(g)⟶16CO2(g)+18H2O(l) If 498 mol of octane combusts, what volume of carbon dioxide is produced at 14.0 ∘C and 0.995 atm?
The combustion of octane, C8H18, proceeds according to the reaction shown. 2C8H18(l)+25O2(g)⟶16CO2(g)+18H2O(l) If 378 mol of...

The combustion of octane, C8H18, proceeds according to the reaction shown. 2C8H18(l)+25O2(g)⟶16CO2(g)+18H2O(l) If 378 mol of octane combusts, what volume of carbon dioxide is produced at 13.0 ∘C and 0.995 atm?

The combustion of octane, C8H18, proceeds according to the reaction shown. 2C8H18(l)+25O2(g)⟶16CO2(g)+18H2O(l) If 346 mol of...

The combustion of octane, C8H18, proceeds according to the reaction shown. 2C8H18(l)+25O2(g)⟶16CO2(g)+18H2O(l) If 346 mol of octane combusts, what volume of carbon dioxide is produced at 15.0 ∘C and 0.995 atm?