2C8H18(g)+25O2(g)→16CO2(g)+18H2O(g) 0.260 mol of octane is allowed to react with 0.760 mol of oxygen. Which is...

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Question

2C8H18(g)+25O2(g)→16CO2(g)+18H2O(g)

0.260 mol of octane is allowed to react with 0.760 mol of oxygen. Which is the limiting reactant?

(i got the limiting reactant of oxygen, but i dont know how to do this next part VVV)

part D: After the reaction, how much octane is left?

science chemistry

Answer 1

Answer #1

Answer 2

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