Question

a ball is thrown upward at 64 feet per second from the top of an 80 feet high building

a ball is thrown upward at 64 feet per second from the top of an 80 feet high building. The height of the ball can be modeled by S(t) = -16t^2 + 64t + 80(feet), where t is the number of seconds after the ball is thrown. describe the graph model
0 0
Add a comment Improve this question Transcribed image text
Answer #1
graph of what? Position vs time?

It will be a parabola, starting on one side at t=0 v=64

The velocity slows to zero, then goes negative until the end.
answered by: eunide
Add a comment
Know the answer?
Add Answer to:
a ball is thrown upward at 64 feet per second from the top of an 80 feet high building
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
  • If a ball is thrown upward at 96 feet per second from a height of 12...

    If a ball is thrown upward at 96 feet per second from a height of 12 feet, the height of the ball can be modeled by S- 12+96t seconds after the ball is thrown. How long after the ball is thrown is the height 152 feet? 16t feet, where t is the number of t takes seconds for the ball to reach th (Type an integer or a simplified fraction. Use a comma to separate answers as needed.) e height...

  • If a ball is thrown upward at 49 meters per second from the top of a...

    If a ball is thrown upward at 49 meters per second from the top of a building that is 35 meters high, the height of the ball can be modeled by S = 35 + 49 - 4.912, where t is the number of seconds after the ball is thrown. Answer parts a through c a. Find the t-coordinate and S-coordinate of the vertex of the graph of this quadratic function. The t-coordinate of the vertex of the graph of...

  • A ball is thrown vertically upward with an initial velocity of 96 feet per second

    A ball is thrown vertically upward with an initial velocity of 96 feet per second. The distance s (in feet) of the ball from the ground after t seconds is s(t)=96t-16t^2a.) at what time will the ball strike the groundb.) for what time t is the ball more than 128 feet above the ground?c.) when will the ball reach its highest peak? how high is it above the ground?

  • A baseball is thrown straight up from the rooftop 192 feet high

    A baseball is thrown straight up from the rooftop 192 feet high. The function s(t)=16t^2+-64t+192 describes the ball's height above the ground,s(t), in feet, t seconds after it was thrown. How long will it take for the ball to hit the ground? Explain

  • An object is thrown upward from a height of 6 feet at a velocity of 64...

    An object is thrown upward from a height of 6 feet at a velocity of 64 feet per second. The height of the object h is a function of time t. h(t) = -16+2 +64t + 6 At what time the function h will reach its maximum value.

  • A ball is thrown vertically upward with an initial velocity of 48 feet per second.

    A ball is thrown vertically upward with an initial velocity of 48 feet per second. The distances (in feet) of the ball from the ground after t seconds is s=48-16t2. (a) At what time t will the ball strike the ground? (b) For what time t is the ball more than 32 feet above the ground?

  • An object is thrown upward at a speed of 182 feet per second by a machine...

    An object is thrown upward at a speed of 182 feet per second by a machine from a height of 14 feet off the ground. The height hh of the object after tt seconds can be found using the equation h=−16t^2+182t+14h=- When will the height be 515 feet? Round to two place When will the object reach the ground?  Round to two places. USE EXCEL SOLVER!! 

  • Fill in the Blanks A golf ball is projected upward from ground level at an initial...

    Fill in the Blanks A golf ball is projected upward from ground level at an initial velocity of 112 ft/sec. The height of a projectile can be modeled by s(t) = -16t+ vot + So, where t is time in seconds, So is the initial height in feet, and Vo is the initial velocity in ft/sec. a. How high will the ball be after 2 sec? O feet b. What is the maximum height the ball reaches? O feet c....

  • A ball A is thrown vertically upward from the top of a 33-m-high building with an...

    A ball A is thrown vertically upward from the top of a 33-m-high building with an initial velocity of 3 m/s. At the same instant another ball B is thrown upward from the ground with an initial velocity of 23 m/s. Determine the height from the ground at which they pass. Determine the time at which they pass.

  • If an object is thrown upward with an initial velocity of 64 ft/sec, its height after t sec is given by h = 64t -16t^2

    If an object is thrown upward with an initial velocity of 64 ft/sec, its height after t sec is given by h = 64t -16t^2. Find the number of seconds the object is in the air before it hits the ground.

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT