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An object is thrown upward at a speed of 182 feet per second by a machine...

An object is thrown upward at a speed of 182 feet per second by a machine from a height of 14 feet off the ground. The height hh of the object after tt seconds can be found using the equation h=−16t^2+182t+14h=-

When will the height be 515 feet?
Round to two place



When will the object reach the ground? 
Round to two places. USE EXCEL SOLVER!! 

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Answer #1

You can skip the half page of the first pic because I have just checked wether the particle cross the highest point Q or not.

The answers are given in the brackets.

Thanks

Rate this solution?Soluion Seu» el a) 2. 2 32.2 Es seco 32. 2.2 32.2t MIhet displaument of eobjeet is ven et at time t-t

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