Question

An electric circuit consists of six resistors and a real battery with Emf = 9 V and an internal resistance r = 0.5ohm . Find the battery current and the terminal voltage of the battery

An electric circuit consists of six resistors and a real battery with Emf = 9 V and an internal resistance r = 0.5ohm . Find the battery current and the terminal voltage of the battery

Answer 1

remember these about Combination of Resistors

if R1 and R2 are the resistances connected in series then effective resiatcne Rnet = R1+R2

if R1 and R2 are connected in parallel, then 1/Rnet =1/R1 +1/R2 or Rnet =   R1R2/(R1+R2)

same current passes through each of the ressitor in series combination and

same votage passes through eacf of the resistor in parallel combination

apply ohms law V = iR

where V = volatge and i = current

so here

6ohms is in series with 6 ohms = 12 ohms

12 parallel with 8 ohms = 12*8/20 = 4.8 ohms

4.8 series with 4 ohms, 2 ohms , 4 ohms

Rnet = 14.8+0.5 = 15.3 ohms

so current i = V/R   = 9/15.3

i = 0.588 AMps

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Vt = e-iR

Vt = 9-(0.588 * 0.5)

Vt = 8.7 Volts