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Six 1.50 V batteries are connected in series, with the positive terminal of one battery connected...

Six 1.50 V batteries are connected in series, with the positive terminal of one battery connected to the negative terminal of the next. What is the emf of the combination? If the internal resistance of each battery is 2.00 Ω, find the terminal voltage when there is a current of 200 mA in the circuit.

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Answer #1

# +-+-+-+- Terminal resistance =R. each battery emf = l. = 1.50 volt internal resistance = r. o 22 each battery Total emf E-b

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