Question

A toboggan approaches a snowy hill moving at 13.3 m/s . The coefficients of static and kinetic friction between the snow and the toboggan are 0.430 and 0.310, respectively, and the hill slopes upward at 45.0 ∘ above the horizontal. Part A Find the acceleration of the toboggan as it is going up the hill. Assume +x axis directed up the hill. ax = m/s2 SubmitMy AnswersGive Up Part B Find the acceleration of the toboggan after it has reached its highest point and is sliding down the hill. Assume +x axis directed up the hill.

Answer 1

force acting on toboggan while going upwards (along - x )= mu*mgcos(theta) + mgsin(theta)

acceleration = mu*gcos(45) + gsin(45) = -9.08709995571 m/s2

negative as acceleration is downhill

as it reaches highest point

force downhill = mgsin(45)

force uphill = mu*mgcos(45)

acceleration = gsin(45)- mu*gcos(45) = -3.9539 m/s2 ax

since it is coming positive means