
Part A -
What is the magnitude of the electric force on charge A in the
figure?
F=______N
Part B
What is the direction of the electric force on charge A in the
figure? Choose best answer.
(a)to the left
(b)to the right
(c)the force is zero
The concepts used to solve the question is a diagram and Coulomb’s law in electrostatics.
At first, draw the diagram of the two point charges and then determine the magnitude and direction of two charges at the required point by using Coulomb’s law in electrostatics.
“Coulomb’s law states that the force of attraction or repulsion between two point charges is directly proportional to the magnitude of the charges and inversely proportional to the square of the distance between the two charges”
Mathematically, it is defined as,

Here,
is the Coulomb constant
and
are the two point charges and
is the distance between two charges.
(A)
The diagram for the three-point charges is drawn below.

The electric force at point A due to the charge at point B is,

Here,
are the two point charges and
is the distance between charges.
Substitute
for
,
for
,
for
and
for 

The electric force at point A due to the charge at point C is,

Here,
are the two point charges and
is the distance between charges.
Substitute
for
,
for
,
for
and
for 

The net force acting on the charge at point A is,

Substitute
for
and
for 

(B)
The net electric force acting at the charge A is 
Therefore, the force acting at the charge A is zero.
Ans: Part AThe magnitude of the net electric force acting on the charge at point A is
.
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