Question

all of the questions

5. How much higher is the absolute pressure 1.2 m under the surface of a pool of fresh water (density = 1.00x103 kg/m?) than at the surface of the pool? A. 1.2x10+03 N/m², calculated from (1.00x103 kg/m)*(1.2 m) B. 1.2x10+04 N/m², calculated from (1.00×10 kg/m3)*(9.8 m/s2)*(1.2 m) C. 12 N/m², calculated from (9.8 m/s2)*(1.2 m) D. 0.012 N/m", calculated from (9.8 m/s2)*(1.2 m)/(1.00×10 kg/m) 6. If the pool in the previous problem were filled with ocean water (density = 1.025x103 kg/m), what then would be the difference between absolute pressure at 1.2 m* depth and pressure at the surface of the water? A. 12 N/m?, calculated from (9.8 m/s2)*(1.2 m) B. 0.011 N/m4, calculated from (9.8 m/s2)*(1.2 m/(1.025x10 kg/m') C. 1.2x10+04 N/m², calculated from (1.025x10 kg/m)*(9.8 m/s?)*(1.2 m) D. 1.2x10+03 N/m?, calculated from (1.025x10 kg/m) (1.2 m) 7. A hydraulic brake cylinder with area 0.00061 m2 applies 1300 N of force to the brakes. What is the pressure in the hydraulic line? A. 0.79 N*m?, calculated from (1300 N)*(0.00061 m²) B. 1.3x10+03 N, calculated from (1300 N) C. 5.3*10*04 N/m, calculated from (1300 N)/sqrt((0.00061 m2) D. 2.1x10+06 N/m², calculated from (1300 N)/(0.00061 m) 8. The brake pedal of a car is attached to a "master cylinder" which transits pressure into the hydaulic system. If the master cylinder has area 0.00023 m2 what force has to be applied in order to cause the 1300 N* force in the brake cylinder of the previous problem? A. 3.4x10*03 N, calculated from (1300 N)*(0.00061 m²/(0.00023 m²) B. 2.1x10+06 N*m, calculated from (1300 N)/(0.00061 m²) C. 0.79 N, calculated from (1300 N)*(0.00061 m) D. 4.9x1002 N, calculated from (1300 N)*(0.00023 m)/(0.00061 m²) E. 5.7x1006N, calculated from (1300 N)/(0.00023 m)

Answer 1

3 p = 1x10 kg /m² 9 = 9.8 m/s2 h = 1.am AP = pgh = (1 x 100 Kg 1m2) 4.8m/s) (1.2m) = 1.2x lot N m2 - Answer > B. 6 In this case, p = 1.025410 Reglam? e Answer C. Area, Force, Pressure A = 0.0006 Ima f = 1300N P = F = A = 1300 0.0006/

P = 2.1 X10 m2 Answer. A = 0.00061 m2 F = 1300N A = 0.00023 m² By Pascal's law, F2 = FixA2 = F, AR = (1300N 160.00023m2). (Ooooolm? F2 = 490.16 N Answer D