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2) The electric field E 5000 N/C , charge q-2 C ' mass m :5 grams. Calc. qE, then apply the acceleration of this charge. Hint: calc. force F newton's 2nd law. A) 1 m/s2 B) 2 m/s2 C) 3 m/s2 D) 4 m/s2 3) The electric field is E 10,000 N/Ci, displacement d - 5 cm at 60 (angle relative to positive x axis), charge q charge in microJoules (106 J) A) 1.25 B) 2.5 C) 3.75 D) 5.0 5 nC. Calc. the work done on the 4l The charg 1.6 X 10-19 c.mass m- 1.7 X 1027 kg, potential

Answer 1

2. B

Acceleration = f/m = qe/m [convert into SI units] a = (2 times 10^-6)(5 times 10^3)/(5 times 10^-3) = 2m/s^2 w = f times s = qe times s [s is displacement section of E] w = (5 times 10^-4) times (10^4) times (5 times 10^-2 cos 60) = 1.25 times 10^-6j = 1.25 microjoules we take E is the direction of the positive xaxis is here if E is in the direction of displacement thenb w� = 2.5 microjoules