Question

1st attempt A gas mixture contains 14.0 g of N2, 2.40 g of H2, and 19.4 g of CH4 What is the mole fraction of CH4 in the mixture? < 05/0 3 OF 5 QUESTIONS COMPLETED

Answer 1

To calculate mole fraction of a component in a reaction mixture , we need to first calculate the number of moles of each component in the mixture by using the formula :

Number of moles = Mass / Molar mass ........1

This is because the mole fraction of a species in a reaction mixture is defined as the ratio of number of moles of that species to the total number of moles of all the species present in the reaction mixture. Thus if a mixture contains 3 species or components A, B and C then the mole fraction of A would be :

Mole fraction of A = (Number of moles of A / Total number of moles of A, B and C ) ............2

1. The given data is :

Mass of N2 = 14.0 g

Mass of H2 = 2.40 g

Mass of CH4 = 19.4 g

Also , we know

Molar mass of N2 = 28 g/mol

Molar mass of H2 = 2 g/mol

Molar mass of CH4 = 16 g/mol

Thus using formula 1 we can calculate number of moles of each as:

mekes Numbes Mass Molan Mass 2ma O-Smel Mass of meles Malar Mass 2a 1.2 mmaR Mars ofCa Mola Mass oles -(~স) Number 19.4 16 1-2125 mel terem tuss C in Male calaulated ng a as i Can MoleEraction CHy 1-2125m (o.smal 2mee 212S m

_Mo২ acke | . 2 ।25 ~२. सिक 2.१।2-ऽ 2 0.५1८

2. In second question the data given is :

Mass of N2 = 9.60 g

Mass of H2 = 2.80 g

Mass of CH4 = 13.8 g

The number of moles of each component in this mixture are calculated as :

১০. ৭-6 ॐं 28 ০.३५३ e९ N১০ %ुD ) ২০৪ । ५ ০. meles (अो 1১.৪ - ০.৪62.S re, Mo২০ ০e ा 1. ५ e१. (০.3५2 + ।. ५e+০.१62S ns2l 1. ५०६९. 2.०5ऽ ९ ০.537