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A gas mixture contains 0.650 mol of N2, 0.200 mol of H2, and 0.200 mol of CH4. Calculate the pressure of the gas mixture andPart 2 (1 pt) *Feedback pressure of H2 0.560 atm Part 3 (1 pt) * Feedback pressure of N2 $ 1.12 atm Part 4 (1 pt) X Feedback

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Answer #1

ne = 0.650 moles nH₂ = 0-20 moles nchu = 0.zomoles n total = 0.65 +0.2+0-2 n total = 1.05 moles v=iu litre T=27+ 273.15 = 300

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