
17. An enzyme-catalyzed reaction has a Vmax of 6 M/s and V, of 4.5 nM/s when...
17. An enzyme-catalyzed reaction has a Vmax of 6 M/s and V, of 4.5 nM/s when the substrate concentration is 1.5 M. What is the Km of this reaction? 2.0.5 b. 1.1 c. 22.5 d. 39 18. From the reaction data below, determine whether the reaction is first-order or second-order. Time (8) Reactant (M) 0 6,67
What is the rate of an enzyme catalyzed reaction if the Vmax is 100µmol S→P/min and the Km is 7 mM and the substrate concentration is 11mM? Is the enzyme working at Vmax? What if the substrate concentration is raised to 25mM?
Need help with number 13! I already asked about number
12. The inverse velocity and inverse substrate concentration relationship for an enzyme-catalyzed reaction is given below V Vmax Vmax S For the hydration of CO2 catalyzed by carbonic anhydrase, it was determined experimentally that (dm s mol 4023.9+ 39.934 at a total enzyme IS] concentration of 2.32 × 10-y mol-dm- What is the value of the Michaelis constant KM for this enzymatic reaction? (B). 9.92x103 mol dm3 (D). 100.8 mol...
An enzyme catalyzes the reaction M↽−−⇀N .
An enzyme catalyzes the reaction M = N. The enzyme is present at a concentration of 3.5 nM, and the Vmax is 1.9 uM -. The Km for substrate M is 2.9 uM. Calculate kcat kcat = 542.86 What values of Vmax and Km would be observed in the presence of sufficient amounts of an uncompetitive inhibitor to generate an a' of 1.5? apparent Vmax = 0.526 UM s-1 apparent Km = 1.2
Vmax of an enzyme-catalyzed reaction is A. the rate observed when the enzyme active sites are saturated with substrate B. independent of the amount of enzyme present C. the rate observed at the highest substrate concentration that can be experimentally obtained D. the initial rate observed at very low substrate concentrations
The following data were recorded for the enzyme-catalyzed reaction. Substrate concentration (M) 6.25 x 100 7.50 x 10 1.00 x 10-4 1.00 x 10-3 Reaction velocity (nM/min) 15 56 60 75 (1) Estimate Km and Vmax- (2) What would V be at S=2.5 x 10-5 ?
The initial rate, V, of an enzyme catalyzed reaction varies with substrate concentration as follows: 106 x Initial rate, Ms SJ, M 0.020 0.585 0.004 0.495 0.002 0.392 0.001 0.312 0.250 0.00066 Determine Vmax and Km for this reaction
At high (saturating) substrate concentrations, the rate of an enzyme-catalyzed reaction approaches Vmax. How close does the reaction rate actually get to Vmax? Determine how high (i.e. how many times Km) the substrate concentration must be for the reaction rate to be: a. 98% Vmax (show your work) (2) b. 99% Vmax (answer only) (1) c. 99.9% Vmax (answer only) (1)
At high (saturating) substrate concentrations, the rate of an enzyme-catalyzed reaction approaches Vmax. How close does the reaction rate actually get to Vmax? Determine how high (i.e. how many times Km) the substrate concentration must be for the reaction rate to be: a. 98% Vmax (show your work) (2) b. 99% Vmax (answer only) (1) c. 99.9% Vmax (answer only) (1)
Biochemistry problem: In an enzyme catalyzed reaction a Vmax of 5 nM/sec has been reported. If the amount of enzyme used in this reaction is 2 μg and the molecular weight of the enzyme is 120,000 then what will be the TON in this enzyme catalyzed reaction?