Biochemistry problem:
In an enzyme catalyzed reaction a Vmax of 5 nM/sec has been reported. If the amount of enzyme used in this reaction is 2 μg and the molecular weight of the enzyme is 120,000 then what will be the TON in this enzyme catalyzed reaction?

Biochemistry problem: In an enzyme catalyzed reaction a Vmax of 5 nM/sec has been reported. If...
An enzyme-catalyzed reaction to the presence of 5 nM of reversible inhibitor yields a Vmax value that is 80% of the value in absence of the inhibitor. The KMvalue is unchanged. a) what type of inhibition is occurring? b) what proportion of the enzyme molecule will have bound inhibitor? c) Draw the Lineweaver-Burk (known as double-reciprocal plot) for uninhibited and inhibited reaction. SHOW ALL YOUR WORK PLEASE
17. An enzyme-catalyzed reaction has a Vmax of 6 M/s and V, of 4.5 nM/s when the substrate concentration is 1.5 M. What is the Km of this reaction? 2.0.5 b. 1.1 c. 22.5 d. 39 18. From the reaction data below, determine whether the reaction is first-order or second-order. Time (8) Reactant (M) 0 6,67
17. An enzyme-catalyzed reaction has a Vmax of 6 M/s and V, of 4.5 nM/s when the substrate concentration is 1.5 M. What is the Km of this reaction? 2.0.5 b. 1.1 c. 22.5 d. 39 18. From the reaction data below, determine whether the reaction is first-order or second-order. Time (8) Reactant (M) 0 6,67
Enzyme Kinetics Problem The initial rate for an enzyme-catalyzed reaction has been determined at a number of substrate concentrations. Data are given below: 5 27 23 65 1. Estimate V and K from a Michaelis-Menten graph of V versus [S] 2. Use a Lineweaver-Burk plot to analyze the same data. a. Determine V and Ka from the Lineweaver-Burk BONUS: If the total enzyme concentration was I nmol/L, what is K?
Enzyme Kinetics Problem The initial rate for an enzyme-catalyzed reaction...
Vmax of an enzyme-catalyzed reaction is A. the rate observed when the enzyme active sites are saturated with substrate B. independent of the amount of enzyme present C. the rate observed at the highest substrate concentration that can be experimentally obtained D. the initial rate observed at very low substrate concentrations
What is the rate of an enzyme catalyzed reaction if the Vmax is 100µmol S→P/min and the Km is 7 mM and the substrate concentration is 11mM? Is the enzyme working at Vmax? What if the substrate concentration is raised to 25mM?
5. The Km of an enzyme of an enzyme-catalyzed reaction is 6.5 uM. What substrate concentration will be required to obtain 55% of Vmax for this enzyme? (10 pts)
What is the Turn Over Number(TON) for an enzyme reaction with a substrate having the Vmax = 0,067 mM secl for 10 mM of the enzyme (a) 0.067 sec1 (b) 0.0067 sec ) (c) 0.67 sec (d) none of these a. (a) b. (b) ic. (c) d. (d)
At high (saturating) substrate concentrations, the rate of an enzyme-catalyzed reaction approaches Vmax. How close does the reaction rate actually get to Vmax? Determine how high (i.e. how many times Km) the substrate concentration must be for the reaction rate to be: a. 98% Vmax (show your work) (2) b. 99% Vmax (answer only) (1) c. 99.9% Vmax (answer only) (1)
At high (saturating) substrate concentrations, the rate of an enzyme-catalyzed reaction approaches Vmax. How close does the reaction rate actually get to Vmax? Determine how high (i.e. how many times Km) the substrate concentration must be for the reaction rate to be: a. 98% Vmax (show your work) (2) b. 99% Vmax (answer only) (1) c. 99.9% Vmax (answer only) (1)