What is E for a cell where E°=1.10 (Cu2++Zn→Cu+Zn2+), [Cu2+]=1.25 M, and [Zn2+]=0.0075 M at SATP? 1.25 V 0.95 V 1.03 V 1.17 V
![E = EO - 0.059 log (a] Et ent of the cell Et standard emt of the hy number of electrons Q + reaction quotient. cell. involved](http://img.homeworklib.com/questions/bb9bc2e0-6e49-11ea-8a73-ebfa53eab2b7.png?x-oss-process=image/resize,w_560)
![E=E² - 0.059 log [2net] E = 1.10 - 0.059 los (0.0075] (1.25 E = 1.10+ 0.065544538) E = 1.1655 = 1.170.](http://img.homeworklib.com/questions/bc584460-6e49-11ea-ba3f-5390adb3acd0.png?x-oss-process=image/resize,w_560)
What is E for a cell where E°=1.10 (Cu2++Zn→Cu+Zn2+), [Cu2+]=1.25 M, and [Zn2+]=0.0075 M at SATP?...
What is E for a cell where Eº=1.10 (Cu2++Zn--Cu+Zn2+), [Cu2+3=1.50 M, and [Zn2+2=0.0050 M at SATP? 0.93 V 1.27 V 1.17 V 1.03 V
Given the following reaction, Cu2+(aq) + Zn(s) → Cu(s) + Zn2+(aq) E° = 1.10 V Use the Nernst equation to calculate the cell potential for the cell described with standard line notation below. Zn|Zn2+(0.5038 M)||Cu2+(0.3981 M)|Cu Units are not required. Report answer to three decimal places.
Choose the correct Nernst equation for the cell Zn + Cu2+ à Zn2+ + Cu E = E° - 0.0296 log(Cu / Zn) E=E° - 0.059 log([Zn2+] / [Cu2+]) E = E° - 0.0296 log(Zn / Cu) E = E° - 0.0296 log([Zn2+] / [Cu2+]) E = E° - 0.0296 log([Cu2+] / [Zn2+]) 20 points
Given: Zn2+ (aq) + 2e Zn(s); E--0.76 V Cu²+ (aq) +20 Cu(s); E° -0.34 V What is the cell potential of the following electrochemical cell at 25°C? Zn(s) | Zn2+(1.0 M) || Cu2+(0.0010 M) Cu(s) a) greater than 1.10 v b) between 0.76 and 1.10 V c) less than 0.42 V d) between 0.00 and 0.76 V e) between 0.34 and 0.76 V
Consider the cell: Zn(s)ǀ(Zn2+(0.20 M)ǁCu2+(0.20 M)ǀCu(s) with Eº(Cu2+/Cu = 0.34 v and Eº(Zn2+/Zn) = –0.76 v a) Write the cell reaction which occurs when the cell produces current and calculate Ecell. b) If each cell compartment contains 25.0 mL of the corresponding metal salt solution and 25.0 mL of 3.00 M NH3(aq) is added to the Cu2+ solution, Ecell = 0.68 v. Use these data to calculate Kf for Cu(NH3)42+. Cu2+(aq) + 4 NH3(aq) ⇄ Cu(NH3)42+
A galvanic cell consists of a Cu(s)|Cu2+(aq) half cell and a Zn(s)|Zn2+(aq) half-cell connected by a salt bridge. Oxidation occurs in the zinc half-cell. The cell can be represented in standard notation as Cu(s)|Cu2+(aq)|Zn(s)|Zn2+(aq) Zn(s)|Zn2+(aq)||Cu(s)|Cu2+(aq) Cu2+(aq)|Cu(s)||Zn(s)|Zn2+(aq) Zn(s)|Zn2+(aq)||Cu2+(aq)|Cu(s) Zn2+(aq)|Zn(s)||Cu(s)|Cu2+(aq) A,B,C,D?
What is the potential of a cell made up of Zn/Zn2+ and Cu/Cu2+ half-cells at 25°C if [Zn²+1 -1.00 Mand (Cu2+] = 0.05 M?
What is the potential of a cell made up of Zn / Zn2+ and Cu / Cu2+ half-cells at 25°C if[Zn2+] = 0.31 M and [Cu2+] = 0.51 M ?
The voltage of the cell combination of Cu/Cu2+ and Zn/Zn2+ is 0.953V. The standard reduction potential for Cu/Cu2+ is expected to be 0.34V. Determine the reduction potential for Zn/Zn2+
For the following cell what is the cell potential under standard conditions? Zn + Cu2+ → Cu + Zn2+ If Cu2+ + 2e- → Cu E° = 0.34V and Zn2+ + 2e- → Zn E° = -0.76 V