Consider the cell: Zn(s)ǀ(Zn2+(0.20 M)ǁCu2+(0.20 M)ǀCu(s) with Eº(Cu2+/Cu = 0.34 v and Eº(Zn2+/Zn) = –0.76 v
a) Write the cell reaction which occurs when the cell produces current and calculate Ecell.
b) If each cell compartment contains 25.0 mL of the corresponding metal salt solution and 25.0 mL of 3.00 M NH3(aq) is added to the Cu2+ solution, Ecell = 0.68 v. Use these data to calculate Kf for Cu(NH3)42+.
Cu2+(aq) + 4 NH3(aq) ⇄ Cu(NH3)42+

Consider the cell: Zn(s)ǀ(Zn2+(0.20 M)ǁCu2+(0.20 M)ǀCu(s) with Eº(Cu2+/Cu = 0.34 v and Eº(Zn2+/Zn) = –0.76 v a)...
Given: Zn2+ (aq) + 2e Zn(s); E--0.76 V Cu²+ (aq) +20 Cu(s); E° -0.34 V What is the cell potential of the following electrochemical cell at 25°C? Zn(s) | Zn2+(1.0 M) || Cu2+(0.0010 M) Cu(s) a) greater than 1.10 v b) between 0.76 and 1.10 V c) less than 0.42 V d) between 0.00 and 0.76 V e) between 0.34 and 0.76 V
What is E for a cell where Eº=1.10 (Cu2++Zn--Cu+Zn2+), [Cu2+3=1.50 M, and [Zn2+2=0.0050 M at SATP? 0.93 V 1.27 V 1.17 V 1.03 V
A galvanic cell consists of a Cu(s)|Cu2+(aq) half cell and a Zn(s)|Zn2+(aq) half-cell connected by a salt bridge. Oxidation occurs in the zinc half-cell. The cell can be represented in standard notation as Cu(s)|Cu2+(aq)|Zn(s)|Zn2+(aq) Zn(s)|Zn2+(aq)||Cu(s)|Cu2+(aq) Cu2+(aq)|Cu(s)||Zn(s)|Zn2+(aq) Zn(s)|Zn2+(aq)||Cu2+(aq)|Cu(s) Zn2+(aq)|Zn(s)||Cu(s)|Cu2+(aq) A,B,C,D?
Given the following reaction, Cu2+(aq) + Zn(s) → Cu(s) + Zn2+(aq) E° = 1.10 V Use the Nernst equation to calculate the cell potential for the cell described with standard line notation below. Zn|Zn2+(0.5038 M)||Cu2+(0.3981 M)|Cu Units are not required. Report answer to three decimal places.
Question 2 (1 point) Consider the following voltaic (galvanic) cell: Zn(s) | 0.010 mol/L Zn2+ (aq) || 1.0 mol/L Cu2+(aq) | Cu(s) What is the predicted cell potential when this cell is operated? 1.04 V 1.10 V 0.76 V 0.34 V 1.16 V
Consider the reaction corresponding to a voltaic cell and its standard cell potential. Zn(s) + Cu2+ (aq) Cu(s) + Zn2+ (aq) ЕО cell = 1.1032 V What is the cell potential for a cell with a 2.440 M solution of Zn2+ (aq) and 0.1636 M solution of Cu²+ (aq) at 439.5 K?
Calculate for the reaction: Zn! Zn2+ (0.60M)| |Cu2+ (0.20M)|Cu Given the following: Cu2+(aq) + Zn(s) Cu(s) + Zn2+(aq) Eo-1.10V
E° (cal.) E° (exp.) 1. Fe(s)| Fe2+ (1 M) || Cu2+ (1 M) | Cu(s) 0.775 V 2. Pb(s) Pb2+ (1 M) || Cu2+ (1 M) Cu(s) 0.461 V 3. Sn(s) | Sn2+ (1 M) || Cu2+ (1 M) | Cu(s) 0.472 V 4. Zn(s) | Zn2+ (1 M) || Cu2+ (1 M) Cu(s) 1.095 V 5. Zn(s) | Zn2+ (1 M) || Cu2+ (1 M + NH3) | Cu(s) 0.928 V a) The Nernst equation for the cell in...
What is E for a cell where E°=1.10 (Cu2++Zn→Cu+Zn2+), [Cu2+]=1.25 M, and [Zn2+]=0.0075 M at SATP? 1.25 V 0.95 V 1.03 V 1.17 V
Candidate l: Zn(s) | Zn2+(aq,0.500 M) I Cu2+(aq, 1.00 M) Cu(s) Candidate 2: Pb(s) | Pb2+(aq, 0.500 M) || Cu2+(aq, 1.00 M) Cu(s) Candidate 3: Mg(s) | Mg2+(aq, 0.500 M) | Pb2+(aq, 1.00 M)| Pb(s) (a) 6 pts) Choose one of the candidate voltaic cells #1, #2, or #3. Draw a schematic cell diagram for the candidate voltaic cell of choice. Clearly label anode, cathode, electrodes, ions and their concentrations, salt bridge, and the flow of electrons. (b) (5 pts)...