Question

Check Answer uuestion 7 of 24 > Chlorine gas can be prepared in the laboratory by the reaction of hydrochloric acid with manganese(IV) oxide. 4 HCl(aq) + MnO,(s) —MnCl, (aq) + 2 H, 0(1) + Cl (9) A sample of 41.5 g Mno, is added to a solution containing 45.3 g HCI. What is the limiting reactant? O MnO2 OHCI What is the theoretical yield of Cl? theoretical yield: If the yield of the reaction is 84.3%, what is the actual yield of chlorine? about us | Careers privacy policy terms of use contact us help Shou MacBook Pro

Answer 1

Reagents are MnO₂ and HCl

So this reaction states that 4 moles of HCl reacts with 1 mole of MnO₂ to produce 1 mole of Cl₂ gas.

Molar mass

MnO₂   86.94 gm/mol HCl 36.5 gm/mol

In this reaction 41.5 gm of MnO₂ reacts with 45.3 gm of HCl

or in other words (41.5/86.94) = 0.48 moles of MnO₂ reacts with (45.3/36.5) = 1.24 moles of HCl

So here HCl is limiting reagent because it is less amount and can react with 1.24/4 =0.31 moles of MnO₂

producing 0.31 mole of Cl₂ gas = 71*0.31 = 22.01 gm (theoretical yield for 100% reaction)

now yield is 84.3% so amount is 22.01*84.3% = 18.55 gm