Question

O Assignment Score: 84.3 Resources 8 Hint Check Answer Question 28 of 28 > Chlorine gas can be prepared in the laboratory by the reaction of hydrochloric acid with manganese/IV) oxide. 4 HCl(aq) + MnO,(s) — MnCl(aq) + 2 H,O(l) + CI, (B) A sample of 35.5 g Mno, is added to a solution containing 50.3 g HCI. What is the limiting reactant? OHCI Mno, What is the theoretical yield of CI? theoretical yield: If the yield of the reaction is 82.5%, what is the actual yield of chlorine? actual yield: gCI,

Answer 1

Limiting reagent = HCl

Amount of Cl2 produced / Theoretical yield = 24.463 g

Actual yield = 20.182g

35.5 a 4 HCl eq. 7 MnO 2 w Mn la cag. + 240 et la I s.3g 35.5g No.dl moles of no = 35.5g - 0.41 mol 86.94 g/mol He= 50.3 g - 1.38 mol 36.469 1mol 4 mol te reacts with Imol Mno, 1.38 mol tee = x 1.38 mol Mno c = 0.345 mol Mno . Limiting Reagent = re. og + 4 mol hce produces Imolce 1:- 1.38 mol ice = I x 1.38 mol ce Amount of Amount of ch a = 0.345 mol cl produced) theoretical wield = 0.345 × 70.9069 = 24.463g Percent yield - Actual pild Theorticalana floo 8.0 82.5 = Actual yield & loo 24.463 Actual yield - 20.1829