What volume (in mL) of 0.24 M KOH(aq) is required to completely neutralize 11 mL of...

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Question

What volume (in mL) of 0.24 M KOH(aq) is required to completely neutralize 11 mL of 0.60 M HBr(aq)? Enter your answer as an i

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Answer 1

Answer #1

Balanced chemical equation is:

HBr + KOH ---> KBr + H2O

Here:

M(HBr)=0.6 M

M(KOH)=0.24 M

V(HBr)=11.0 mL

According to balanced reaction:

1*number of mol of HBr =1*number of mol of KOH

1*M(HBr)*V(HBr) =1*M(KOH)*V(KOH)

1*0.6 M *11.0 mL = 1*0.24M *V(KOH)

V(KOH) = 27.5 mL

Answer: 28 mL

Answer 2

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