Question

QUESTION 1 Calculate the volume of 0.5 M KOH solution in mL required to completely neutralize 25.0 mL of 0.1 M HNO3 solution (a) 25 (b) 5 (c) 10 (d) none of the choices is correct QUESTION 2 20 mL of 0.2 M NaOH solution is required to completely neutralize 20 mL of a standard H2SO4 solution (a) 0.1 M (b) 0.2 M (c) 0.5 M (d) None of the choices is correct Click Save and Submit to save and submit. Click Save All Answers to save all answers.

Answer 1

In question 1 part b is correct and I question 2 part a is correct

and base 0.59 KOH 'n wel nuetralize 25.0nel of o. JM HNO, kon & Ko ton HINO & H +Nge No. of moles of Ho. Molarity = mole/rowme & Mokes - Molarity X Moles of H+ = 0.ly 0.025L un = 0.002s moles - 4 Volume of kot used Molarity - Male volume a Voleme - Mole Polarity. It is nuchalization of acid a cono. of moles of Het = No of moles of ono {from A) volenne = 0.0025 = 0.005 L = 5 mL Aug 0.5 2ome of 0.2 M Maol nepalire zome of standard Hason NoH Hatton the so Zuo esouz- Moles of on = 0.29 0.02 L = 0.004 mole - Molarity I conch of the ser or to required fornuetralcration Modacity = Mole { couch of 4t = conch of on} Volume Molality = 0.004 - 0.025 0.2M H₂sou contains 2HB. Therefore conch of thSoy = 0.3 M oor M theo y