Calculate the number of grams of acetic acid needed to prepare 100. mL of 1.00 M...

Question

Question

Calculate the number of grams of acetic acid needed to prepare 100. mL of 1.00 M acetic acid. The molecular weight of acetic acid is 60.1 g/mol.

science chemistry

Answer 1

Answer #1

Moles of acetic acid = molarity * volume ( in L )

= 1.00 * (100*10^-3)

= 0.1 moles

weight = moles * molar mass

= 0.1 * 60.1

= 6.01 grams

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Answer 2

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