Question

Determine the bond order from the molecular electron configurations. (o)(0 (a2)9(02*) (2p) bond order: (ou)(0)(02) (02)(p)(p
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Answer #1

1)

Number of electron in bonding orbital = 2+2+4 = 8

Number of electron in Anti bonding orbital = 2+2 = 4

Bond Order = 0.5*(Number of electron in bonding orbital - Number of electron in Anti bonding orbital)

= 0.5*(8 - 4)

= 2.0

Answer: 2.0

2)

Number of electron in bonding orbital = 2+2+2+4 = 10

Number of electron in Anti bonding orbital = 2+2+4 = 8

Bond Order = 0.5*(Number of electron in bonding orbital - Number of electron in Anti bonding orbital)

= 0.5*(10 - 8)

= 1.0

Answer: 1.0

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