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Which type of molecular orbital has a maximum electron density along the internuclear axis but zero density in a plane perpen
What is the valence electron molecular orbital electron configuration of F2? (02)2(0* 2s)-(02p)2(12p) 4 (n*2p)4 (02)2(0*2s)-(
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Answer #1

1.   Sigma star (σ*) orbital : antibonding molecular orbital in have a region of zero electron probability / density (a nodal plane) perpendicular to the internuclear axis. For sigma orbital electron density along the internuclear axis and between the nuclei has cylindrical symmetry :  all cross-sections perpendicular to the internuclear axis are in this cylinder.

2.  Sigma (σ) orbital : are used to describe build up electron density along two nuclei forming bond. It denotes a bonding orbital :  nuclei are attracted to the accumulation of electron density in the internuclear region.

3. pi (\pi) orbital :Sum of these side-to-side interactions increases the electron probability in the region above and below a line connecting the nuclei, so it is a bonding molecular orbital that is called a pi (π) orbital.It has a nodal plane along inter-nuclear axis.

4. C(6) : valence electron : 2s2,2p2

C2 = ( σ2s)2 (σ*2s)2 (π2p)4

5. N(7) : valence electron : 2s2,2p3

N2 = ( σ2s)2 (σ*2s)2 (π2p)4( σ2p)2

6. pi (\pi) orbital :  It is result of side-to-side interaction which  increases the electron density in the region above and below axis connecting the nuclei, it is a bonding molecular orbital that is called a pi (π) orbital.

7.

O(8) : valence electron : 2s2,2p4

O2 = ( σ2s)2 (σ*2s)2 ( σ2p)2 (π2p)4 (π*2p)2   

So, bond order is = 1/2(8-4) = 2

8.

F(9) : valence electron : 2s2,2p5

F2 = ( σ2s)2 (σ*2s)2 ( σ2p)2 (π2p)4 (π*2p)4

9 .   O(8) : valence electron : 2s2,2p4

O2 = ( σ2s)2 (σ*2s)2 ( σ2p)2 (π2p)4 (π*2p)2

10. Of these O2 is paramagnetic , as it has 2 electrons in degenerate π*2p orbitals, as per hund's rule these are filled : so, two unpaired electrons make is paramagnetic.

others have no electron unpaired ,thus are diamagnetic.

11. N2 = ( σ2s)2 (σ*2s)2 (π2p)4( σ2p)2

bond order is = 1/2(8-2) = 3

12. C2 = ( σ2s)2 (σ*2s)2 (π2p)4

bond order is = 1/2(6-4) = 2.

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